0.48x^2=5x+16

Solution for 0.48x^2=5x+16 equation:

0.48x^2=5x+16

We move all terms to the left:

0.48x^2-(5x+16)=0

We get rid of parentheses

0.48x^2-5x-16=0

a = 0.48; b = -5; c = -16;
Δ = b2-4ac
Δ = -52-4·0.48·(-16)
Δ = 55.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{55.72}}{2*0.48}=\frac{5-\sqrt{55.72}}{0.96}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{55.72}}{2*0.48}=\frac{5+\sqrt{55.72}}{0.96}
$